shorten a string without cutting words

Question

How to shortening a string without cutting words? For example, I have a string called Hello World, whose length is 11. I want to shorten its length to less than 6, which would be Hello W, but W is not a full word, we need to remove it. So the result is ony a word Hello. The following code is to solve the problem, written in python.

Code

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#!/usr/bin/env python
# -*- coding: utf-8 -*-
import unittest
def break_word(src, length):
if length <= 0:
return ''
elif length >= len(src):
return src.rstrip()
for i in range(length, -1, -1):
if src[i] == ' ':
return src[:i].rstrip()
return ''
class TestBreakWord(unittest.TestCase):
def test_breakword(self):
# zero length
self.assertEqual(break_word('Hello World', 0), '')
# no word is hit
self.assertEqual(break_word('Hello World', 2), '')
# exactly a word
self.assertEqual(break_word('Hello World', 5), 'Hello')
# exactly a word plus a space
self.assertEqual(break_word('Hello World', 6), 'Hello')
# the second word isn't hit
self.assertEqual(break_word('Hello World', 7), 'Hello')
# exactly two words
self.assertEqual(break_word('Hello World', 11), 'Hello World')
# two spaces
self.assertEqual(break_word('Hello World', 5), 'Hello')
self.assertEqual(break_word('Hello World', 6), 'Hello')
self.assertEqual(break_word('Hello World', 7), 'Hello')
self.assertEqual(break_word('Hello World', 8), 'Hello')
# space in the end
self.assertEqual(break_word('Hello World ', 11), 'Hello World')
self.assertEqual(break_word('Hello World ', 12), 'Hello World')
# two spaces in the end
self.assertEqual(break_word('Hello World ', 11), 'Hello World')
self.assertEqual(break_word('Hello World ', 12), 'Hello World')
self.assertEqual(break_word('Hello World ', 13), 'Hello World')
if __name__ == '__main__':
unittest.main()

Result

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./words.py
.
----------------------------------------------------------------------
Ran 1 test in 0.000s
OK
Process finished with exit code 0
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